The slope of line 2x-3y-7=0
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Given line is 2x-3y-7=0
so, 2x-3y=0+7
2x-3y=7
1) = 3y=2x-7
y= 2x-7/3
therefore, slope of (1) is2/3 . The requried line is parallel to (1) so its slope is also 2/3y intercept of requried line=4
therrfore, by using y= mx+c from the equation of the requried line is y=2x+4/3 or 2x-3y +12 = 0
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