The slope of line joining the points P(4,k) and Q(-3,-2) is -2/7.Find the value of k
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Answered by
3
Slope=y2-y1/x2-x1
Here
-2/7=-2-k/-3-4
K=4
Here
-2/7=-2-k/-3-4
K=4
aman784:
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Answered by
7
Slope = y2-y1/x2-x1
= - 2/7=-2-k/-3-4
=-2/7=-2-k/-7
=-2/7=-(2+k)/-7
=-2/7= 2+k/7
=-2=2+k
=-2-2=k
=-4=k
K=-4
Hope it is helpful..
= - 2/7=-2-k/-3-4
=-2/7=-2-k/-7
=-2/7=-(2+k)/-7
=-2/7= 2+k/7
=-2=2+k
=-2-2=k
=-4=k
K=-4
Hope it is helpful..
hope it is helpful if so plz mark as brainliest
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