Question

The slope of line perpendicular to the line 5x-4y+6=0 is

Answer 1

Start with 5x-4y-6=0

Isolate y

-4y = -5x + 6

y = %285%2F4%29x+-+6%2F4

...

slope is 5%2F4

A perpendicular line will have a negative inverse slope of -4%2F5

...

Using the slope and the point (-2, 3),

y - 3 = -4%2F5(x--2)

y - 3 = -4%2F5(x+2)

y - 3 = %28-4%2F5%29x+%2B+%28-4%2F5%29%282%29

y = %28-4%2F5%29x+-+8%2F5+%2B+3

y = %28-4%2F5%29x+-+8%2F5+%2B+3%285%2F5%29

y = %28-4%2F5%29x+-+8%2F5+%2B+15%2F5

highlight_green%28y=%28-4%2F5%29x%2B7%2F5%29