Question

the slope of
line
whose
find
inclination is
is 15 degree​

Answer 1

Answer:

$The \: slope \: of \: the \: line \: Which \: makes \: an \: angle \: of \: 15° \: = tan15 \\ = tan(45 - 30) \\ = \frac{1 - tan30}{1 + tan30} \\ = \frac{1 - \frac{1}{ \sqrt{3} } }{1 + \frac{1}{ \sqrt{3} } } \\ = \frac{ \sqrt{3} - 1 }{ \sqrt{3} + 1 } \\ = \frac{ \sqrt{3} - 1 }{ \sqrt{3} + 1 } \times \frac{ \sqrt{3} - 1}{ \sqrt{3} - 1 } \\ = \frac{ {( \sqrt{3} - 1)}^{2} }{3 - 1} \\ = \frac{3 + 1 - 2 \sqrt{3} }{2} \\ = \frac{4 - 2 \sqrt{3} }{2} \\ = 2 - \sqrt{3}$