Math, asked by roshansav71gmailcom, 3 months ago

The slope of straight line passing throught (5,8) and
(-3,4) is​

Answers

Answered by soundharya12904
0

Answer:

x-2y+11=0

y-8/4-8=x-5/-3-5

y-8/-4=x-5/-8

-8(y-8)=-4(x-5)

-8y+64=-4x+20

4x-8y+64-20=0

4x-8y+44=0

÷4

x-2y+11=0

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