The slope of straight line passing throught (5,8) and
(-3,4) is
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Answer:
x-2y+11=0
y-8/4-8=x-5/-3-5
y-8/-4=x-5/-8
-8(y-8)=-4(x-5)
-8y+64=-4x+20
4x-8y+64-20=0
4x-8y+44=0
÷4
x-2y+11=0
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