Math, asked by pranjaliwani, 1 year ago

the slope of tangent to the curve y=x^2-x at pt. where y=2 cuts the curbe in first quadrant is

Answers

Answered by Anonymous
0
the point (2,2) is in the first quadrant (the point where y = 2 cuts the curve) the slope at this point is 2(2) - 1 = 3
Answered by saka82411
2
Hi friend,

The point (2,2) is in the first quadrant

The point where y = 2 cuts the curve.

By taking differentiation,

X^2-x=2x-1..

Y=2x-1------------------(1)

Apply y=2 in equation (1)

the slope at this point is 2(2) - 1 = 3.....

Hope this helps you...
Please mark it as brainliest answer... ☺☺☺☺
Similar questions