the slope of tangent to the curve y=x^2-x at pt. where y=2 cuts the curbe in first quadrant is
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the point (2,2) is in the first quadrant (the point where y = 2 cuts the curve) the slope at this point is 2(2) - 1 = 3
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Hi friend,
The point (2,2) is in the first quadrant
The point where y = 2 cuts the curve.
By taking differentiation,
X^2-x=2x-1..
Y=2x-1------------------(1)
Apply y=2 in equation (1)
the slope at this point is 2(2) - 1 = 3.....
Hope this helps you...
Please mark it as brainliest answer... ☺☺☺☺
The point (2,2) is in the first quadrant
The point where y = 2 cuts the curve.
By taking differentiation,
X^2-x=2x-1..
Y=2x-1------------------(1)
Apply y=2 in equation (1)
the slope at this point is 2(2) - 1 = 3.....
Hope this helps you...
Please mark it as brainliest answer... ☺☺☺☺
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