The slope of tangent to the curve y=x^3-2x^2+4 at x=2 is
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Answer:
Slope of tangent to the curve y = x³-2x²+4 at x= 2 is 4
Step-by-step explanation:
given :- y = x³ -2x² +4
- differentiate y with respect to x
∴ dy/dx = d(x³-2x²+4)
⟹ dy/dx = 3x² - 4x + 0
⟹dy/dx = 3x² - 4x
⟹dy/dx = m (slope of tangent)
⟹ dy/dx (at x = 2) = 3(2)² - 4(2)
⟹ dy/dx (m)= 12 - 8 = 4
- ∴ Slope of tangent (at x = 2) is 4
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Step-by-step explanation:
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