Math, asked by yashikamohite0417, 9 months ago

The slope of tangent to the curve y=x^3-2x^2+4 at x=2 is​

Answers

Answered by TheLifeRacer
7

Answer:

Slope of tangent to the curve y = x³-2x²+4 at x= 2 is 4

Step-by-step explanation:

given :- y = x³ -2x² +4

  • differentiate y with respect to x

∴ dy/dx = d(x³-2x²+4)

⟹ dy/dx = 3x² - 4x + 0

⟹dy/dx = 3x² - 4x

⟹dy/dx = m (slope of tangent)

⟹ dy/dx (at x = 2) = 3(2)² - 4(2)

⟹ dy/dx (m)= 12 - 8 = 4

  • Slope of tangent (at x = 2) is 4

Answered by nandini247618
1

Step-by-step explanation:

here is ur answer

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