the slope of tangent to the curve y=x2+2ex+2 is (0,4)
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Step-by-step explanation:
solution - equation of curve is y=e
2x
tangent to the curve is
dx
dy
=2e
2x
(
dx
de
x
=e
x
)
At points (0,1), the tangent is
(
dx
dy
)
(0,1)
=2e
2(0)
(
dx
dy
)
(0,1)
=2e
0
[e
0
=1]
dx
dy
0,1
=2
when the slope is 2, and solve the tangent
meets y axis the coordinate is 0,
Hence the tangent meets the x axis at (2,0)
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