Question

the slope of the line going the points (3,4)
and (4,1) is​

Answer 1

Given point

$\tt \to \: p(3,4) \: and \: q(4,1)$

Formula

$\tt \to \: m = \dfrac{y _{2} -y_1}{x_2 - x_1}$

We have

$\tt \to \:x_1 = 3,y_1 = 4,x_2 = 4 \: and \: y_2 = 1$

Now Put the Value on formula

$\tt \to \: m = \dfrac{1 - 4}{4 - 3}$

$\tt \to \: m = \dfrac{ - 3}{1} = - 3$

Answer

$\tt \to \: m = - 3$

More Information

More Information Formula use in coordinate Geometry

1)Slope Intercept form

$\tt \to \: y = mx + c$

2) To Find angles

$\tt \to \: tan \theta = \dfrac{m_1 - m_2}{1 + m_1m_2}$

3) For Perpendicular

$\tt \to \: m_1m_2 = - 1$

4)Slope

$\tt \to \: m = \dfrac{y _{2} -y_1}{x_2 - x_1}$

Answer 2

Given points:

• p(3,4) and q(4,1)

Using Formula:-

• m = y2 - y1/x2 - x1

step-by-step solution:-

We have

⟶ x1 = 3, y1 = 4 ,x2 = 4 and y2 = 1

Now Put the Value on formula

⟶ 1 - 4/ 4 - 3

⟶ - 3/ 1 = - 3

Answer

⟶ m = - 3

More information:

More Information Formula use in coordinate Geometry

1)Slope Intercept form

⟶ y = mx + c

2) To Find angles

⟶ tan∅ = m1 - m2/1 + m1m2

3) For Perpendicular

⟶ m1m2 = - 1

4)Slope

⟶ m = y2 - y1 /x2 - x1