Question

the slope of the line joining (-a, a) and(a, a+a√3)
a) 2/√3
b) 1/√3
c) √3
d) √3/2​

Answer 1

Answer:

$d) \frac{ \sqrt{3} }{2}$

Step-by-step explanation:

slope = (y2 - y1)/(x2 - x1)

here y1 = a snd y2 = a+a square root of 3

x1 = -a and x2 = a

then, slope = (a+a square root 3 - a)/(a-(-a))

= (a+a square root 3 - a)/(a+a)

= (a square root 3)/(2a)

= (square root 3)/(2)