Question

the slope of the line normal to the curve f(x） 2cos4x at x= pi/12 is​

Answer 1

Answer is (c)

Step-by-step explanation:

f(x)=2cos4x

f'(x)=2[-sin4x] (4)

=-8sin4x

at f'(x) at x= π/12=-8sin π/3

= -8√3/2= -4√3=m

= so slope of the normal

=-1/m =-1/4√3

=1/4√3×√3/√3=√3/12