Question

The slope of the line touching both the parabolas y^2=4x and x^2=-32y is

Answer 1

Answer:

Y^2 = 4X

X^2 = 32Y

X = Y^2 / 4

X^2 = Y^4 / 16 =32Y

Y^4 / Y = 32 * 16 =512.

Y = 8..

X = 64 / 4 = 16...