Question

the slope of the normal to curve y=logsinx at x=pi/2 is
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Answer 1

Answer:

0

Step-by-step explanation:

y=logsinx

differentiate with respect to x

dy/dx=1/sinx*cosx

dy/dx=cot x

dy/dx at x= π/2

cot x=cot π/2=0

The slope of normal to a curve is given as,

m = −1 / dy/ dx=-1/0=0