The slope of the normal to the curve y = 2x^ 2 + 3 sin x at x = 0 is (A) 3 (B)1/3 (C) −3 (D)-1/3
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HELLO DEAR,
given, y = 2x² + 3sinx
let f(x) = y = 2x² + 3sinx
f'(x) = 4x + 3cosx
the slope if the normal = -1/f'(x)
hence, the slope of normal at point x = 0 is
-1/(4*0 + 3*1) = -1/3
slope = -1/3
hence, option (D) is correct.
I HOPE ITS HELP YOU DEAR,. THANKS
given, y = 2x² + 3sinx
let f(x) = y = 2x² + 3sinx
f'(x) = 4x + 3cosx
the slope if the normal = -1/f'(x)
hence, the slope of normal at point x = 0 is
-1/(4*0 + 3*1) = -1/3
slope = -1/3
hence, option (D) is correct.
I HOPE ITS HELP YOU DEAR,. THANKS
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