the slope of the straight line 3x-9y+12=0 is
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Answer:
1/3
Step-by-step explanation:
First, find x and y intercepts...
y-int:
3x-9y+12=0
x=0
9y+12=0
9y=-12
y=-4/3
(0,-4/3)
x-int:
y=0
3x+12=0
3x=-12
x= -4
(-4, 0)
m=y2-y1/x2-x1
= -4/3 - 0 /-4-0
= -4/3 / -4
m= 1/3
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