Question

The slope of the straight line which is both tangent and normal to the curve

Answer 1

If a line is tangent to one point and normal to another point on the curve x=4t2+3,y=8t3−1 then the question is to find out the slope of such a line.

Slope of curve at (4t21+3,8t31−1) is 3t1.Now it is normal to the curve at point t2,then slope of normal at that point is −13t2.Equating we get 9t1t2=−1.I couldn't proceed after this.Any help shall be highly appreciated. Thanks

Answer 2

Answer:

Step-by-step explanation:

Slope of curve at (4t21+3,8t31−1)(4t12+3,8t13−1) is 3t13t1.Now it is normal to the curve at point t2t2,then slope of normal at that point is −13t2−13t2.Equating we get 9t1t2=−19t1t2=−1.I couldn't proceed after this.

Thanks

Hope it helps you....