Question

the slope of the tangent to the curve y=3x^2-5x+6 at (1,4)

Answer 1

okkkk.....
y = 3x^2-5x+6
if we will find dy/dx
dy/dx= 6x-5 okkkk
now we will find the slope of tangent at point (1,4) okkkk
dy/dx=Slope of the tangent ,,,, at point 1,4
then ,,,,
slope of tangent = 6(1)-5
= 1