The slope of the tangent to the curve y = 3x2 + 3 at x = 0 is
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Answer:
Answer is 3.
Step-by-step explanation:
By substituting x=0 in y=3x^2+3 we get the y=3.
And by substituting x=1 in y=3x^2+3 we get y=6, so by using formula of y2-y1/x2-x1, we get slope =3.
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