Question

The slope of the tangent to the curve y=x^2 - X at the point, where the line y=2 cuts the curve in the 1st quadrant, is

Answer 1

The point at which line y=2 cut the curve can be found out by
       2=x^2-x
       x^2-x-2=0
     on solving we will get, 
     x=-1,2
 since, the point is in first quadrant, So, x=2

Thus, point is (2,2).
Slope of the curve can be found out by differentiating the the equation of curve with respect to the x.
  dy/dx= 2x-1
Now, put the value of x
   dy/dx=2(2)-1=4-1=3
Therefore, the slope is 3.

Answer 2

Answer:

Step-by-step explanation: