Question

The small piston of a hydraulic lift has an area of 6 cm 2and its large piston has an area of 54 cm 2 . A 50 N force is applied to the small piston. What is the weight of the load can be lifted by the large piston?

Answer 1

Answer:

Area 1 = 6 cm²

Area 2 = 54 cm²

Force 1 = 50 N

Force 2 = ? N

We know the formula that :

Force 2 by Force 1 = Area 2 by Area 1

Force 2 by 50 = 54 by 6

Force 2 = 50 × 54 divided by 6

Force 2 = 50 × 9

Force 2 = 450 N Answer .

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