Question

the small piston of a hydraullic lift has diameter of 8.0cm, and its large portion has a diameter of 40 cm the lift raisesa load of 15,000 n. whatisthe force that must be applied to the small position

Answer 1

Hydraulic lift works on the principle of pascal's law

P=a1F1=a2F2

applying the given formula to the question.

0.901.2×104=0.2FF=0.900.24×104=2.67×103N