the smaller of the two complementary angles is 36°smaller than the large one find the angles
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Answered by
18
Let the smaller angle be 'x'
Then larger angle=x+36
Now,we have
x+x+36=90
2x=54
x=27
Hence,smaller angle=x=27
larger angle=x+36=63
Then larger angle=x+36
Now,we have
x+x+36=90
2x=54
x=27
Hence,smaller angle=x=27
larger angle=x+36=63
Answered by
8
Hi Dear
let the larger angle is x°
ATQ smaller angle is x-36°
ATGC x-36 = 90-x°
2x = 126
x = 63°
90-x= 90-63 = 27°
SO the angles are 63°,27°
let the larger angle is x°
ATQ smaller angle is x-36°
ATGC x-36 = 90-x°
2x = 126
x = 63°
90-x= 90-63 = 27°
SO the angles are 63°,27°
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