Question

The smaller of two complementary angles is 36 smaller than the larger one. Find the angles.

Answer 1

$\textbf{Answer}$

$\textbf{Two angles are complimentary if-}$
$\textbf{The sum of two angles is 90°}$
Or
$\textbf{They form a right angle together}$

Lets get back to the question,
Smaller of two complimentary angles is 36 smaller than the other angle.

Lets suppose the smaller angle is A°

=> Larger angle = A° + 36

Since sum of both angles is 90,

=> A° + (A° + 36) = 90

=> 2A° = 90 - 36

=> 2A° = 54

=> A° = 54/2

=> A° = 27

=> A° + 36 = 27 + 36 = 63

$\textbf{Lets verify now,}$

27° + 63° = 90° (Hence both are complimentary angles as sum is 90°)

$\textbf{So required angles are 27° and 63°}$

$\textbf{Hope My Answer Helped}$

$\textbf{Thanks}$

Answer 2

$\textbf{Question :-}$

The smaller of two $\textbf{complementary angles}$ is 36° than the larger one.

Find the angels = ?

$\textbf{Solution :-}$

Complementary angle =>

The complementary angles are the angel having the the $\textbf{sum of 90}$°

Now , your question :-

Let's suppose the $\textbf{smaller angle}$ = x°

Then the larger one will be = x° + 36°

According to the question :-

=》[ x° + 36° ] + x° = 90°

=》2x° + 36° = 90°

=》2x° = 90° - 36°

=》2x° = 54°

=》x° = 27°

Hence , the $\textbf{smaller angle will be 27}$°

Now , the larger angle will be

=》x° + 36°

=》27° + 36°

=》63°

Hence , the $\textbf{larger angle will be}$ = 36°

$\textbf{Thanks !!!}$

$\textbf{be brainly}$☺