Question

The smaller side of rectangle is 6cm less than that of it's larger side .if it's perimeter is 28cm,

a) what is the sum of lengths of larger and smaller side's

b) what are the length of the side's ?
___________________
# unwanted answers will be reported.​

Answer 1

Given :-

Smaller side of the rectangle less than it's larger side = 6 cm

Perimeter of the rectangle = 28 cm

To Find :-

The sum of lengths of larger and smaller sides.

The length of the sides.

Solution :-

We know that,

• p = Perimeter
• l = Length
• b = Breadth

Let the larger side and the smaller side be x and x - 6 respectively.

Then, given

Length (l) = x

Breadth (b) = x - 6

Perimeter (p) = 28 cm

By the formula,

$\underline{\boxed{\sf Perimeter \ of \ a \ triangle=2(Length+Breadth)}}$

Substituting their values,

Perimeter = $\sf 2(x+x-6)=28$

$\sf =28 = 2(2x - 6)$

$\sf = 28 = 4x - 12$

$=\sf 28 + 12 = 4x$

$\sf =\dfrac{40}{4} =x$

$\sf =x=10$

Hence,

Length of the larger side = x = 10

Length of the smaller side = $\sf x-6=10-6=4$

Therefore,

a) The sum of lengths of larger and smaller side would be,

Length of the larger side + Length of the smaller side = Sum

$\sf 10+4=14$

Therefore, the sum is 14

b) The length of the sides are,

Length of larger side = 10 cm

Length of the smaller side = 4 cm

Answer 2

Answer:

thanks for free points mate

u from Kottayam ah ?