Question

The smallest 5 digit number that is divisible by 19 is ?

Answer 1

Hey!
#Your Ans
____________

we know that smallest 5 digit number

=> 10000
now

divide the 10000 by 19
we get remainder 6

so

10000+13 = 10013

so ,

five digit number +( divisior-remainder)

==> 10000 + (19-6)

==> 10000+13

==> 10013

Therefore smallest five digit number which is divisible by 19
=> 10013

Hope it's helpful ✌✌

Answer 2

Given:

The smallest 5 digit number that is divisible by 19 is?

To Find:

Find the number

Solution:

To find the smallest 5 digit number divisible by 19 we will need to divide 10000 by 19 to get the value remainder and then this remainder is added back to 10000 to get the number required,

10000 can be expressed in the form of 19a+k where k is the remainder, so we have,

$10000=\frac{10000}{19}\\=19*526+6\\=19*a+6$

So as we can see that we have an excess of 6 and we need to add some more to get it fully divisible by 19 which will be (19-6)=13

So adding 13 to 10000,

Five-digit number=10013

Hence, the smallest 5 digit number that is divisible by 19 is 10013.