Question

the smallest 5-digit number, which is exactly divisible by 9 , 15 , 18​​

Answer 1

LCM of the divisors= 90

Divide 10000 by 90. We get 111 as the quotient. Ignore the remainder.

111x90 9990. This is the largest 4 digit number exactly divisible by 9, 15 and 18.

To get the smallest 5 digit number as needed, simply add 90.

We get= 9990+90= 10080

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Answer 2

$\huge\red{\boxed{\orange{\mathcal{\overbrace{\underbrace{\fcolorbox{red}{pink}{\underline{\red{❥Answer࿐}}}}}}}}}the smallest$

111x90= 9990. This is the largest 4 digit number exactly divisible by 9, 15 and 18. To get the smallest 5 digit number as needed, simply add 90.