the smallest angle of a triangle is one fifth the sum of the other two and the largest angle exceeds the sum of the other two by 20°. find the largest angle of the triangle.
(A) 100°
(B) 90°
(C) 120°
(D) 110°
[From chapter: Pairs of linear equations in two variable]
[Answer: (A) 100°]
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Step-by-step explanation:
let smallest angle be s and largest angle is l respectively,third angle is 180-s-l
by given condition
s=(180°-(s+l)+l)/5
=(180°-s)/5
=36°-s/5
s=(5*36°)/6
s= 30 °
l=(s+180°-s-l)+20°
= (180°-l)+20°
=200°-l
2l=200°
l=200°/2
l=100°
third angle =180°-100°-30°
=50°
so largest (l) is 100°
smallest angle (s) is 30°
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