Question

the smallest angle of triangle whose sides are 6+root 12 ,root 48, root =24=?

Answer 1

Answer:

smallest angle is 6 root 12 ok if it is good pls comment

Answer 2

Answer:

Pi/6 ans

Step-by-step explanation:

Let a =(6+rot 12), b = rot24, c= rot 48

a²= (48+12rot12), b²=24, c²=48

Therfore b is smallest

CosB = a²+c²-b²/ 2ac. = ( *Formula)

Now (6+rot12)² + 48 - 24 / 2(6+rot12)(rot48)

=rot3/2

B=pi/6