Question

The smallest angular momentum of electron in hydrogen atom will be
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Answer 1

Answer:

h/2(pi)

Explanation:    the formula is

root of{l(l+1)} . h/2(pi)

so the smallest angular momentum will be when the electron is in the first orbit and s-orbital so that the value of l=0... hence the ans is h/2{pi}

Answer 2

The smallest angular momentum of electron in hydrogen atom will be  $\dfrac{h}{2\pi}$ .

We need to find the smallest angular momentum of electron in hydrogen atom .

We know , angular momentum of electron in hydrogen atom is given by :

$L_n=\dfrac{nh}{2\pi}$

Here , n is the orbit number .

h is plank's constant .

For , minimum value of angular momentum , n should be 1 .

Therefore , putting n = 1 .

We get :

$L=\dfrac{h}{2\pi}$

Hence , this is the required solution .

Learn More :

Atomic Structure

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