Question

The smallest by which 1080 must be divided to get each number a perfect cube is? ​

Answer 1

$\sqrt[3]{1080}$

$\sqrt[3]{2 \times 2 \times 2 \times 3 \times 3 \times 3 \times 5}$

We observe that 5 doesn't form any cube. So, we will divide 1080 by 5

$1080 \div 5$

$216$

$\sqrt[3]{216}$

$= 6$

Answer 2

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