Question

The smallest division on main scale of a vernier caliper is 1 mm and 10 vernier scale divisions coincide with 9 main scale divisions. While measuring the length of a wire, the zero mark of the vernier scale lies between 12.2 cm and 12.3 cm and the fifth division of vernier scale coincides with a main scale division. The length
of wire is​

Answer 1

The length of the wire is 12.25 cm

Step-by-step explanation:

Given

The smallest division on the main scale is 1 mm

10 vernier scale divisions coincide with 9 main scale division

Therefore, the least count of vernier is

$\text{LC}=\frac{\text{Smallest division on main scale}}{\text{No. of vernier divisions}}$

$\implies \text{LC}=\frac{1\text{ mm}}{10}$

$\implies \text{LC}=0.1$ mm

$\implies \text{LC}=0.01$ cm

Since the zero mark lies between 12.2 cm and 12.3 cm and fifth division of vernier scale coincides with main scale division

Therefore, the reading will be

$=12.2+5\times\text{ LC}$

$= 12.2+5\times 0.01$

$=12.2+0.05$

$= 12.25$ cm

Therefore, the length of the wire is 12.25 cm

Hope this answer is helpful.

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