Question

the smallest no. by which 2352 must be multiplied find the perfect square of the no.

Answer 1

Hi ,

Prime factorisation of 2352 = 2 × 2 × 2 × 2 × 3 × 7 × 7 .

Common factor = 2 , 2 and 7.

And,

Uncommon factor = 3

So,

3 must be multiplied to 2352 to make it a perfect square.




3 × 2352 = 7056



Square root of 7056 is 84.

Answer 2

2 | 2352

2 | 1176

2 | 588

2 | 294

3 | 147

7 | 49

7 | 7


2352 = ( 2 × 2 × 2 × 2 × 3 × 7 × 7)

2352 = (2 × 2) (2× 2) (7× 7) ×3

The pair of 2, 2 and 7 are completed but pair of 3 is not completed. So, if we multiply the given number by 3,the number will become perfect square.

Required number = 3