Math, asked by shanu5933, 8 months ago

The smallest number among the three consecutive numbers whose sum is 258

Answers

Answered by Mehekjain

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Your answer....

$let \: the \: three \: \: consecutive \: numbers \: be \:$

$(x \: ) + (x - 1) + (x + 1)$

$(x \: ) + (x - 1) + (x + 1) = 258$

$3x + 0 = 258$

$3x = 258$

$x = \frac{258}{3}$

$x = 86$

$so \: the \: numbers \: are$

$(x) = 86$

$(x + 1) = 87$

$(x - 1) = 85$

$hence \: the \: smallest \: no \: is \: 85$

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