The smallest number in a Pythagorean triplet is 14, find the other two numbers.
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Answer:
here your answer..........
Step-by-step explanation:
Phythagorean triplets are numbers in form
2m , m²+1 and m²-1
So If one of the numbers is 14
let it be 2m.
Then, 2m = 14
m = 14/2
m= 7
So other two numbers are -
m²+1 = 7²+1 = 49+1 = 50
m²-1 = 7²-1 = 49-1 = 48
So, The triplets are 14,48 and 50
hope it' will help you...............
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