The smallest number of different digits formed by using the digits 3 1 0 5 and 7 is________.
Answers
Given :- The smallest number of different digits formed by using the digits 3 1 0 5 and 7 is________.
Solution :-
→ Total digits in ascending order = 0, 1, 3, 5 and 7 = Total 5
now, we need to make smallest five digit number with given digits .
since a five digit number we can not start with 0 at left most side . so we will start with second smallest digit that is 1 and then we will use 0 .
so,
→ Smallest five digit number will be :-
- 1 = Ten thousand place .
- 0 = Thousand place.
- 3 = Hundred place .
- 5 = Tens place .
- 7 = unit place .
then,
→ The required smallest five digit number will be = 10357 .
[ Note :- if we need smallest number using all digits we can write 01357 also which can be read as 1357 only. ]
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Given : digits 3 1 0 5 and 7
To Find : The smallest number of different digits formed by using the given digits
Solution:
As smallest number of different digits to be formed hence we need to use 0 as well .
And there are 5 digit so number will be 5 digit number
And 0 can not be used at highest place value
Highest place value should have least Digit
so 1st digit will be 1
Then 0 can be used
further similarly 3 , 5 and 7 can be used
so smallest number formed is 10357
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