Question

The smallest number that divides 64 and 72 and leave the remainder 12 and 7 respectively

Answer 1

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Answer 2

Answer:

Answer is 13

Explaination:

here subtract dividend -divisor in

So 64-12=52

& 72-7=65

Now H.C.F of 52 and 65 is 13

Hence 13 is the smallest number

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