The smallest number which is divisible by both 306 and 657
Answers
we have to find smallest number which is divisible by 306 and 657
indirectly question ask us to find LCM of 306 and 657.
prime factors of 306 = 2 × 3² × 17
prime factors of 657 = 3 × 3 × 73
so, lowest common multiple or LCM of 306 and 657 = 2 × 3² × 17 × 73
= 2 × 9 × 17 × 73
= 18 × 17 × 73
= 306 × 73
= 22338
hence, smallest number is 22338 which is divisible by 306 and 657.
Step-by-step explanation:
Basically we need to find the LCm of 306 and 657 for getting smallest number divisible by both the numbers.
Prime factorisation of 306 = 2 × 3² × 17
Prime factorisatiom of 657 = 3 × 3 × 73
Now, LCM of 306 and 657 = 2 × 3×3 × 17 × 73
= 2 × 9 × 17 × 73
= 306 × 73
= 22338
Therefore, smallest number divisible by 306 and 657 is 22338.
Thank you! Hope it helps!