Math, asked by akshatagrawal5737, 11 months ago

The smallest number which leaves no remainder when divided by 54 and 66

Answers

Answered by bhairab141
3

Answer:

The required number is the LCM of 54 and 66.

Now ,

54=2×3×3×3

66=2×3×11

LCM of 54 and 66 is =2×3×3×3×11

=594

The required number is 594

Answered by 140201718
0

Answer:

Step-by-step explanation:

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