Question

the smallest number which leaves remainder 5 when divided by 15 20 and 35

Answer 1

Hey fella,here is your answer

425 is the correct answer as L.C.M. of 15,20 ad 35 is 420.

So required no.=420+5=425.

Then it leaves remainder 5 in each case.

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Answer 2

Firstly, we will find the LCM of 15, 20 and 35


15 = 3 × 5

20 = 2 × 5 × 2

35 = 7 × 5


LCM = 420



Now, we will add 5 to 420


420 + 5 = 425



$\therefore{The \: number \: is \: 425}$