Math, asked by 8978200810, 7 months ago

The smallest number which leaves remainders 8 and 12 when divided by 28 respectively is​

Answers

Answered by 8bvanshpandit
0

Answer:

the answer is 4

Step-by-step explanation:

when we divide 28 ÷8 we get remainder 4 and when we divide 28 ÷ 12 we again get remainder 4 only

hope it helps and have a safe learning

Answered by Ansh919
0

Answer: 36 and 40

Step-by-step explanation:

smallest number divided by 28 be 28 because smallest multiple of 28 is 28.

now, if it will leave remainder 8,

then, number is 28+8= 36

if, it will leave remainder 12,

then, number is 28+12=40.

so, the smallest number which leaves remainders 8 and 12 when divided by 28 respectively are

36 and 40.

I hope it will be helpfull to you.

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