Math, asked by avantika1806, 10 months ago

The smallest number which when diminished by 5, is divisible by 12, 16, 18, 21, and 28 is_

Answers

Answered by kartik2507

0

finding LCM of 12, 16, 18, 21, 28

we get 1008

add 5 to 1008

1013 is the required number

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