The smallest number which when diminished by 7, is divisible by 12, 16, 18, 21 and 28 is
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Answer:
- LCM
12 = 2 x 2 x 3 = 22 x 3
16 = 2 x 2 x 2 x 2 = 24
18 = 2 x 3 x 3 = 2 x 32
21 = 3 x 7 = 3 x 7
28 = 2 x 2 x 7 = 22 x 7
The Product of all factors with highest powers
LCM = 24 x 32 x 7 = 2 x 2 x 2 x 2 x 3 x 3 x 7
LCM = 1008
- Required Number = 1008 + 7 = 1015
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