Question

The smallest number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:

Answer 1

548

• The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: [A]. = 548.

Answer 2

Answer:

LCM= 548

Step-by-step explanation:

$\rightarrow$ To find the least common factor, we'll first subtract 8 from all the given number -

• 12-8= 4
• 15-8=7
• 20-8= 12
• 54-8= 46

$\rightarrow$ We'll Fnd LCM now - 548