Question

The smallest number which when divided by 20, 25, 35, 40 leaves a remainder of 14, 19, 29 and 34 respectively is _____
(Pls tell the answer with step by step explanation)

Answer 1

Let us first find the factors of the given numbers 20,25,35 and 40 to find the LCM of these numbers:

20=2×2×5

25=5×5

35=5×7

40=2×2×2×5

Therefore, LCM(20,25,35,40)=5×5×2×2×2×7=1400

Now we find the difference of the given numbers as follows:

20−14=6, 25−19=6, 35−29=6 and 40−34=6

So, we get 6 less than the divisor in each case and thus the required number is 1400−6=1394

Hence, the number is 1394.

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Answer 2

Answer:

1394

Step-by-step explanation: