Question

The smallest number which when divided
by 20, 25, 35 and 40 leaves a remainder of
14, 19, 29 and 34 respectively, is
(A) 1394
(B) 1404
(C) 1664
(D) 1406
Plz give the explanation step by step ​

Answer 1

First follow me than I will give you a correct answer with explanation

What is the smallest number which when divided by 20, 25, 35, 40 leaves a remainder of 14, 19, 29, 34 respectively?

This is a question of multiple divisors with multiple remainders.

Although the remainders seem different, but they are the same when we take their negative counterparts.

R[N/20]=14R[N/20]=14 or (−6)(−6)

R[N/25]=19R[N/25]=19 or (−6)(−6)

R[N/35]=29R[N/35]=29 or (−6)(−6)

R[N/40]=34R[N/40]=34 or (−6)(−6)

So, we can see NN leaves the same remainder (-6) when divided by 20, 25, 35 or 40.

So, N=LCM(20,25,35,40)+(−6)N=LCM(20,25,35,40)+(−6)

Or, N=1394N=1394 (Answer)

Like my answer

Follow me

Mark me as brainlist

Hope it help