Question

the smallest number which when divided by 30,45,75,60, leaves a remainder of 21,36,66,51 respectively ​

Answer 1

Answer:

891 is the answer

plz like me

Answer 2

The smallest number which when divided by 30,45,75,60, leaves a remainder of 21,36,66,51 respectively is 891.

Step-by-step explanation:

It is given that a smallest number which when divided by the divisors 30, 45, 75 and 60 leaves remainders 21, 36, 66 and 51 respectively.

1. Firstly, we will subtract the remainders from each of their divisors i.e.,

30 – 21 = 9

45 – 36 = 9  

75 – 66 = 9

60 – 51 = 9

2. Now, we will find the L.C.M of the divisors i.e.,

30 = 2 * 3 * 5

45 = 3 * 3 * 5

75 = 3 * 5 * 5

60 = 2 * 2 * 3 * 5

∴ L.C.M = 2 * 2 * 3 * 3 * 5 * 5 = 2² * 3² * 5² = 900

3. Finally, we know that the required number will be 9 less than the LCM of 30, 45, 75 and 60.

∴ The required smallest number = 900 – 9 = 891

---------------------------------------------------------------------------------------

Also View:

Find the smallest number which when divided by 28 and 32 leaves remainder 8 and 12 respectively.

https://brainly.in/question/2321970

The smallest number which leaves remainder 5 when divided by 15 20 and 35 .

https://brainly.in/question/5754778