Question

The smallest number which when divided by 35 and 126 leaves the remainder 7 in each

Answer 1

Answer:

35-7=28

126-7=119

in 119 and 28

119=28×4+7

28=7×4+0--------7

Answer 2

Answer:

The answer is 630

637 when divided by 35 and 126 leaves the remainder 7

Step-by-step explanation:

First we will have to find the Lowest Common Multiplier or LCM of 35 and 126 which is 630

35 = 5 × 7

126 = 2 × 3 × 3 × 7

So the LCM of 35 and 126 is 5 × 7 × 2 × 3 × 3 = 630

The number should also leave a remainder when divided by 35 and 126 so we must add 7 to 630.

So our final answer is 630.

So 637 when divided by 35 and 126 leaves the remainder 7

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