Question

The smallest number which when divided by 4,6,10,15 gives the same remainder'3'is________
A. 39
B. 57
C. 63
D. 123

Answer 1

Prime factorization of 4 = 2 * 2

Prime factorization of 6 = 2 * 3

Prime factorization of 10 = 2 * 5

Prime factorization of 15 = 3 * 5

LCM(4,6,10,15) = 2 * 2 * 3 * 5

                        = 60.

So, the required number = 60 + 3 = 63.   ----- Option(C)

Hope it helps!

Answer 2

• At first  L.C.M of 4 , 6 , 10 and 15 .

                   L.C.M = 60

         The required no. is 60 + 3 = 63.

So

• 63 is the no.

Thank u.