Question

The smallest number which when increased by 3 and is divisible by 27, 48. 51 is :

Answer 1

The smallest number which when increased by 3 and is divisible by 27, 48, 51 is 7341.

Step-by-step explanation:

Given : Number which when increased by 3 and is divisible by 27, 48, 51.

To find : The smallest number ?

Solution :

First we find the LCM of the number

2 | 27  48  51

2 | 27  24  51

2 | 27   12  51

2 | 27    6  51

3 | 27    3  51

3 |  9     1   17

3 |  3     1   17

17 | 1     1   17

   |  1     1    1

$LCM(27,48,51)=2\times 2\times 2\times 2\times 3\times 3\times 3\times 17$

$LCM(27,48,51)=7344$

As number is increased by 3.

So, $7344-3=7341$

Therefore, the smallest number which when increased by 3 and is divisible by 27, 48, 51 is 7341.

#Learn more

Find the smallest number which when increased by 3, is divisible by 18 ,48 and 80

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