Question

The smallest number which when increased by 7 is exactly divisible by 20, 25 ,and 30

Answer 1

Step-by-step explanation:

lcm of 20,25,30 are 300

that means 300 is the number which is exactly devisible by 20,25,30

but smallest number which when increased by 7 to exactly devisible is =300-7=293

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Answer 2

Answer:

300.the solution is given below